5x^2+1x+1=0

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Solution for 5x^2+1x+1=0 equation:


Simplifying
5x2 + 1x + 1 = 0

Reorder the terms:
1 + 1x + 5x2 = 0

Solving
1 + 1x + 5x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
0.2 + 0.2x + x2 = 0

Move the constant term to the right:

Add '-0.2' to each side of the equation.
0.2 + 0.2x + -0.2 + x2 = 0 + -0.2

Reorder the terms:
0.2 + -0.2 + 0.2x + x2 = 0 + -0.2

Combine like terms: 0.2 + -0.2 = 0.0
0.0 + 0.2x + x2 = 0 + -0.2
0.2x + x2 = 0 + -0.2

Combine like terms: 0 + -0.2 = -0.2
0.2x + x2 = -0.2

The x term is 0.2x.  Take half its coefficient (0.1).
Square it (0.01) and add it to both sides.

Add '0.01' to each side of the equation.
0.2x + 0.01 + x2 = -0.2 + 0.01

Reorder the terms:
0.01 + 0.2x + x2 = -0.2 + 0.01

Combine like terms: -0.2 + 0.01 = -0.19
0.01 + 0.2x + x2 = -0.19

Factor a perfect square on the left side:
(x + 0.1)(x + 0.1) = -0.19

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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